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Question: Answered & Verified by Expert

0.05 cm thick coating of silver is deposited on a plate of 0.05 m2 area. The number of silver atoms deposited on plate are _______×1023. (At mass Ag =108, d=7.9 g cm-3 Round off to the nearest integer.

ChemistrySome Basic Concepts of ChemistryJEE MainJEE Main 2024 (30 Jan Shift 1)
Solution:
1488 Upvotes Verified Answer
The correct answer is: 11

Volume of silver coating =0.05×0.05×10000=25 cm3

Given, Density =7.9 g cm-3

Density = Mass/ Volume 

Mass of silver deposited =25×7.9 g

Moles of silver atoms = mass / molar mass =25×7.9108

Number of silver atoms =25×7.9108×6.023×1023

=11.01×1023

Ans. 11

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