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Question: Answered & Verified by Expert
0.1M KMnO4 is used for following titration. What volume of the solution in mL will be required to react with 0.158g of Na2S2O3?
Not balanced: S2O32-+MnO4-+H2OMnO2(s)+SO42-+OH-
ChemistryRedox ReactionsJEE Main
Options:
  • A 26.7 mL
  • B 50 mL
  • C 65 mL
  • D 75 mL
Solution:
1118 Upvotes Verified Answer
The correct answer is: 26.7 mL
S+22O32-+MnO4-+H2OMnO2(s)+S+6O42-+OH-
'n' factor of Na2S2O3=8
'n' factor of KMnO4=3
m.eq of Na2S2O3= m.eq of KMnO4
0.158 158 ×8×1000=0.1×V×3
V=26.7 mL

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