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0.15g of a substance dissolved in 15g of solvent boiled at a temperature higher by 0.216oC than that of the pure solvent. The molecular weight of the substance is [Given: Molal elevation constant for the solvent is 2.16Kkg mol 1 ]
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Solution:
1199 Upvotes Verified Answer
The correct answer is: 100
Here it is given that w=0.15g, ΔT b =0 .216 o C
W=15g, K b =2.16Kkg mol 1
Substituting values in the expression, m=1000×Kb×wΔTb×W
m= 1000×216×0.15 0.216×15 =100g/mol

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