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$\int_0^2 \frac{2 x-2}{2 x-x^2} d x$ is equal to
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Verified Answer
The correct answer is:
$0$
Let $I=\int_0^2 \frac{2 x-2}{2 x-x^2} d x$
Put $2 x-x^2=t \Rightarrow(2-2 x) d x=d t$
$$
=-\int_0^0 \frac{d t}{t}=0
$$
Put $2 x-x^2=t \Rightarrow(2-2 x) d x=d t$
$$
=-\int_0^0 \frac{d t}{t}=0
$$
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