∫ 0 π 2 sec ⁡ x n sec ⁡ x n + cosec ⁡ x n d x =

Question

∫ 0 π 2 sec ⁡ x n sec ⁡ x n + cosec ⁡ x n d x =, π 2, π 3, π 4, π 6

MARKS App · Accepted Answer

∫ 0 π 2 sec ⁡ x n sec ⁡ x n + cos ⁡ e c x n d x ..... (i) ⇒ I = ∫ 0 π 2 sec ⁡ π 2 - x n sec ⁡ π 2 - x + cosce ⁡ π 2 - x n n d x ⇒ I = ∫ 0 π 2 cosce ⁡ x n cosce ⁡ x n + sec ⁡ x n d x ..... (ii) Adding equation (i) and (ii) 2 I = ∫ 0 π 2 d x ⇒ 2 I = x 0 π 2 ⇒ π 4

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