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Question: Answered & Verified by Expert
0π2sec xnsec xn+cosec xndx= 
MathematicsDefinite IntegrationJEE Main
Options:
  • A π2
  • B π3
  • C π4
  • D π6
Solution:
2745 Upvotes Verified Answer
The correct answer is: π4
0π2sec xnsec xn+cos ec xndx  ..... (i)
  I=0π2sec π2-xnsec π2-x+ cosceπ2-xnndx
  I=0π2cosce xncoscexn + sec xndx ..... (ii)
Adding equation (i) and (ii)
2I=0π2dx 
  2I=x0π2
 π4

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