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$\int_{0}^{2}\left[\mathrm{x}^{2}\right] \mathrm{dx}$ is equal to where [] if GIF
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Verified Answer
The correct answer is:
$5-\sqrt{2}-\sqrt{3}$
Hint:
$\int_{0}^{1} 0 \mathrm{dx}+\int_{1}^{\sqrt{2}} 1 \cdot \mathrm{dx}+\int_{\sqrt{2}}^{\sqrt{3}} 2 \cdot \mathrm{d} x+\int_{\sqrt{3}}^{2} 3 \mathrm{~d} x$
$=5-\sqrt{2}-\sqrt{3}$
$\int_{0}^{1} 0 \mathrm{dx}+\int_{1}^{\sqrt{2}} 1 \cdot \mathrm{dx}+\int_{\sqrt{2}}^{\sqrt{3}} 2 \cdot \mathrm{d} x+\int_{\sqrt{3}}^{2} 3 \mathrm{~d} x$
$=5-\sqrt{2}-\sqrt{3}$
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