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Question: Answered & Verified by Expert
020πsinx+cosx2dx is equal to:
MathematicsDefinite IntegrationJEE MainJEE Main 2022 (26 Jul Shift 2)
Options:
  • A 10π+4
  • B 10π+2
  • C 20π-2
  • D 20π+2
Solution:
1376 Upvotes Verified Answer
The correct answer is: 20π+2

Let I=020πsinx+cosx2dx

We know that the period of sinx+cosx is π2

i.e. I=400π2sinx+cosx2dx

I=400π21+sin2xdx

=40x-cos2x20π2=40π2-cosπ2+cos02

I=20π+2

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