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Question: Answered & Verified by Expert
032+x2dx=
MathematicsDefinite IntegrationJEE Main
Options:
  • A limn1n2n+12+22++3n2n2
  • B limn1n3n+12+22++6n2n2
  • C limn1n6n+12+22++9n2n2
  • D limn1n3n+12+22++3n2n2
Solution:
1009 Upvotes Verified Answer
The correct answer is: limn1n6n+12+22++9n2n2

Let 2+x2=f(x)

032+x2dx=03fxdx

Now, 03fxdx=limn1nr=13nfrn

=limn1nr=13n2+rn2

=limn1n2×3n+12+22+32++3n2n2

=limn1n6n+12+22+32++3n2n2

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