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$\varepsilon_0$ and $\mu_0$ are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are $2 \varepsilon_0$ and $1.5 \mu_0$ respectively, the refractive index of the medium will nearly be
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The correct answer is:
$\sqrt{3}$
We know
$\begin{aligned} & \text { Refractive index }=\frac{\sqrt{\mu \varepsilon}}{\sqrt{\mu_0 \varepsilon_0}} \\ & =\frac{\sqrt{(1.5) \mu_0(2) \varepsilon_0}}{\sqrt{\mu_0 \varepsilon_0}} \\ & =\sqrt{3}\end{aligned}$
$\begin{aligned} & \text { Refractive index }=\frac{\sqrt{\mu \varepsilon}}{\sqrt{\mu_0 \varepsilon_0}} \\ & =\frac{\sqrt{(1.5) \mu_0(2) \varepsilon_0}}{\sqrt{\mu_0 \varepsilon_0}} \\ & =\sqrt{3}\end{aligned}$
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