0.01 M solution of KCI and C a C l 2 are separately prepared in water. The freezing point of KCI is found to be - 2 o C . What is the freezing point of C a C l 2 aq. solution if it is completely ionized?

Question

0.01 M solution of KCI and C a C l 2 are separately prepared in water. The freezing point of KCI is found to be - 2 o C . What is the freezing point of C a C l 2 aq. solution if it is completely ionized?, - 3 o C, + 3 o C, - 2 o C, - 4 o C

MARKS App · Accepted Answer

i f o r K C l = 2 , i f o r f o r C a C l 2 = 3 ∆ T f ∝ i ∆ T f ( K C l ) ∆ T f C a C l 2 = 2 3 ∆ T f C a C l 2 = 3 2 × 2 = 3 o C Freezing point of C a C l 2 = - 3 o C

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