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\( 0.06 \%(\mathrm{w} / \mathrm{v}) \) aqueous solution of urea is isotonic with
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The correct answer is:
\( 0.01 \mathrm{M} \) glucose solution
Molarity of \( 0.06 \%\left(\frac{w}{v}\right) \) aqueous solution of urea
\[
\begin{array}{l}
=\frac{0.06 \times 1000}{60 \times 100} \\
=0.01 M
\end{array}
\]
As osmotic pressure \( (\Pi)= \) CRT
Therefore, \( 0.01 \mathrm{M} \) solution of urea will be isotonic with \( 0.01 \mathrm{M} \) glucose solution
\[
\begin{array}{l}
=\frac{0.06 \times 1000}{60 \times 100} \\
=0.01 M
\end{array}
\]
As osmotic pressure \( (\Pi)= \) CRT
Therefore, \( 0.01 \mathrm{M} \) solution of urea will be isotonic with \( 0.01 \mathrm{M} \) glucose solution
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