0.078 g of hydrocarbon occupy 22.4 m L of volume at 1 a t m and 0 ° C. The empirical formula of the hydrocarbon is C H . The molecular formula is -

Question

0.078 g of hydrocarbon occupy 22.4 m L of volume at 1 a t m and 0 ° C. The empirical formula of the hydrocarbon is C H . The molecular formula is -, C 2 H 2, C 4 H 4, C 6 H 6, C 8 H 8

MARKS App · Accepted Answer

Molar mass of hydrocarbon can be determtextnd with the help of ideal gas equation: P V = n R T P V = w M R T 1 × 22.4 1000 L = 0.078 M × 0.082 × 273 k m = 78 g M o l e c u l a r f o r m u l a = n × E m p e r i a l f o r m u l a n = m o l e c u l a r f o r m u l a e m p i r i a l m a s s E m p i r i a l m a s s = C H So, Empirical mass =12 H=13 ∴ n = 78 13 = 6 M o l e c u l a r f o r m u l a = C H 6 = C 6 H 6

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