0.1 M K M n O 4 is used for the following titration. What volume of the solution in ml will be required to react with 0.158 g N a 2 S 2 O 3 . 5 H 2 O ? 3 S 2 O 3 2 - + M n O 4 - + H 2 O → 8 M n O 2 + 6 S O 4 2 - + 2 O H -

Question

0.1 M K M n O 4 is used for the following titration. What volume of the solution in ml will be required to react with 0.158 g N a 2 S 2 O 3 . 5 H 2 O ? 3 S 2 O 3 2 - + M n O 4 - + H 2 O → 8 M n O 2 + 6 S O 4 2 - + 2 O H -, 1.7 ml, 0.17 ml, 17 ml, 1.07 ml

MARKS App · Accepted Answer

As per as the balanced equation given below 3 S 2 O 3 2 - + 8 M n O 4 - + H 2 O → 8 M n O 2 + 6 S O 4 2 - + 2 O H - 3 moles of N a 2 S 2 O 3 = 8 moles of K M n O 4 3 × 248 g of N a 2 S 2 O 3 = 8 × 158 g of K M n O 4 0.158 g of N a 2 S 2 O 3 = 8 × 158 × 0.158 3 × 248 = 0.27 g K M n O 4 Volume = W t . × 1000 M o l a r i t y × M o l . W t . = 0.27 × 1000 0.1 × 158 = 17 ml .

Search any question & find its solution

Looking for more such questions to practice?