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$0.5 \mathrm{~g}$ of an acid is neutralised by $40 \mathrm{cc}$ of $0.125 \mathrm{~N} \mathrm{NaOH}$. The equivalent mass of the acid is
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100
Equivalent moles of $\mathrm{NaOH}=$ Equivalent moles of acid
$N_{1} V_{1}=\frac{\text { Weight }}{\text { Equivalent mass }}$ $40 \times 10^{-3} \times 0.125=\frac{0.5}{\text { Equivalent mass }}$ $\therefore$ Equivalent mass of acid $=100$
$N_{1} V_{1}=\frac{\text { Weight }}{\text { Equivalent mass }}$ $40 \times 10^{-3} \times 0.125=\frac{0.5}{\text { Equivalent mass }}$ $\therefore$ Equivalent mass of acid $=100$
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