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$0.5 \mathrm{M}$ of $\mathrm{H}_2 \mathrm{SO}_4$ is diluted from 1 litre to 10 litre, normality of resulting solution is
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$0.1 \mathrm{~N}$
Molarity of $\mathrm{H}_2 \mathrm{SO}_4=0.5$
Normality of $\mathrm{H}_2 \mathrm{SO}_4\left(N_1\right)=0.5 \times 2=1$ $N_1 V_1=N_2 V_2$
$1 \times 1=N_2 \times 10$ or $\quad N_2=\frac{1}{10}=0.1 N$.
Normality of $\mathrm{H}_2 \mathrm{SO}_4\left(N_1\right)=0.5 \times 2=1$ $N_1 V_1=N_2 V_2$
$1 \times 1=N_2 \times 10$ or $\quad N_2=\frac{1}{10}=0.1 N$.
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