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Question: Answered & Verified by Expert
0.85% aqueous solution of NaNO3 is apparently 90% dissociated. The osmotic pressure of solution at 300 K is
ChemistrySolutionsNEET
Options:
  • A 4.674 atm
  • B 46.74 atm
  • C 2.46 atm
  • D 4.674 mm Hg
Solution:
1276 Upvotes Verified Answer
The correct answer is: 4.674 atm
M=W×1000mol.wt.×V
Molarity =1000cm3×0.85g100cm3×85gmol-1=0.1molL-1
NaNO3Na++NO3-
So i=1-α+α-α1
=1+α=1+0.90=1.90
π=iCRT=1.90×0.1×0.082×300
=4.674 atm.

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