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Question: Answered & Verified by Expert
$\int_{-1}^1 \log \left(\frac{2-x}{2+x}\right) d x=$
MathematicsDefinite IntegrationMHT CETMHT CET 2022 (08 Aug Shift 1)
Options:
  • A 1
  • B -1
  • C 0
  • D 2
Solution:
1751 Upvotes Verified Answer
The correct answer is: 0
$\begin{aligned} & \int_{-1}^1 \log \left(\frac{2-x}{2+x}\right) \mathrm{d} x=0 \\ & \because \log \left(\frac{2-x}{2+x}\right) \text { is an odd function. }\end{aligned}$

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