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Question: Answered & Verified by Expert
1.84g mixture of CaCO 3 and MgCO 3 when heated to constant weight of 0.96g as residue. Find the mass of CaCO 3 (in grams) in the mixture. M CaCO 3 =100 g/mole, M MgCO 3 =84 g/mole
ChemistrySome Basic Concepts of ChemistryJEE Main
Solution:
1076 Upvotes Verified Answer
The correct answer is: 1.00
MgCO 3 + CaCO 3 MgO + CaO + 2 CO 2 g 1.8 4 - x g x g 0.8 8 g Moles { 1 · 8 4 - x 8 4 x 1 0 0 0 · 8 8 4 4
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Apply POAC to C

1.8 4 - x 8 4 × 1 + x 1 0 0 × 1 = 0.8 8 4 4 × 1 = 0.0 2

1 8 4 - 1 0 0  x + 8 4  x = 1 6 8

  1 6 = 1 6  x

  x = 1  g

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