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Question: Answered & Verified by Expert
1 C electricity deposits
ChemistryElectrochemistryMHT CETMHT CET 2010
Options:
  • A $10.8 \mathrm{~g}$ of $\mathrm{Ag}$
  • B $96500 \mathrm{~g}$ of $\mathrm{Ag}$
  • C electrochemical equivalent of Ag
  • D half of electrochemical equivalent of Ag
Solution:
1722 Upvotes Verified Answer
The correct answer is: electrochemical equivalent of Ag
From Faraday's first law,
mass, $w=Z \cdot Q$
when,
$$
Q=1 \mathrm{C}
$$
$w=Z=$ electrochemical equivalent.

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