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$\int \sqrt{1+\cos x} d x$ equals
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$2 \sqrt{2} \sin \frac{x}{2}+c$
$\begin{aligned} & I=\int \sqrt{1+\cos x} d x=\int \sqrt{2 \cos ^2(x / 2)} d x \\ & I=\sqrt{2} \int \cos (x / 2) d x=2 \sqrt{2} \sin (x / 2)+c\end{aligned}$
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