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Question: Answered & Verified by Expert
$\int \sqrt{1+\cos x} d x$ is equal to
MathematicsIndefinite IntegrationWBJEEWBJEE 2010
Options:
  • A $2 \sqrt{2} \cos \frac{\mathrm{x}}{2}+\mathrm{C}$
  • B $2 \sqrt{2} \sin \frac{\mathrm{x}}{2}+\mathrm{C}$
  • C $\sqrt{2} \cos \frac{x}{2}+C$
  • D $\sqrt{2} \sin \frac{x}{2}+C$
Solution:
1537 Upvotes Verified Answer
The correct answer is: $2 \sqrt{2} \sin \frac{\mathrm{x}}{2}+\mathrm{C}$
Hints: $\int \sqrt{1+\cos x} d x=\sqrt{2} \int \cos \left(\frac{x}{2}\right) d x=2 \sqrt{2} \sin \left(\frac{x}{2}\right)+c$

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