1 g of a complex [Cr(H 2 O) 5 Cl]Cl 2 ⋅ H 2 O (mol. Wt. 266.5) was passed through a cation exchanger to produce HCl . The acid liberated was diluted to 1 litre. The normality of this acid solution is

Question

1 g of a complex [Cr(H 2 O) 5 Cl]Cl 2 ⋅ H 2 O (mol. Wt. 266.5) was passed through a cation exchanger to produce HCl . The acid liberated was diluted to 1 litre. The normality of this acid solution is, 5 × 1 0 – 3 N, 7.5 × 1 0 – 3 N, 7.5 × 1 0 – 2 N, 7.5 × 1 0 – 1 N

MARKS App · Accepted Answer

Mole of complex = W m o l . wt. = 1 266.5 1 mole of complex produces 2 mole HCl [Cr(H 2 O) 5 Cl]Cl 2 → Cr(H 2 O)Cl] 2+ 2Cl – Mole of HCl formed = 1 266.5 × 2 N HCl = n V × n − factor = 2 266 .5×1 = 7 .5 × 10 –3 N

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