1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5 . The ratio of the elevation in their boiling points, ∆ T b A ∆ T b B , is: (assuming they have the same molar mass)

Question

1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5 . The ratio of the elevation in their boiling points, ∆ T b A ∆ T b B , is: (assuming they have the same molar mass), 10 : 1, 1 : 5, 1 : 0.2, 5 : 1

MARKS App · Accepted Answer

Elevation in Boiling point ∆ T b = i × k b × m For non-electrolyte, i = 1 m= Molar mass of solute m 1 = molality of solution 1 m 2 = molality of solution 2 ∆ T b 1 = k 1 × 1 × m 1 , m 1 = 1 100 × m × 1000 = 10 m ∆ T b 2 = k 2 × 1 × m 2 , m 2 = 1 100 × m × 1000 = 10 m m 1 = m 2 ∆ T b 1 ∆ T b 2 = k 1 k 2 = 1 : 5

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