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$1 \mathrm{~g}$ of polymer having molar mass $1,60,000 \mathrm{~g}$ is dissolved in $800 \mathrm{~mL}$ water. Calculate the osmotic pressure in pascal at $27^{\circ} \mathrm{C}$. $\left(R=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mole}^{-1}\right)$
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The correct answer is:
$19.4$
$\pi=C R T$
$\pi=\frac{1}{1.6 \times 10^5} \times \frac{8.314 \times 300}{800 \times 10^{-6}}=19.4 \mathrm{~Pa}$
$\pi=\frac{1}{1.6 \times 10^5} \times \frac{8.314 \times 300}{800 \times 10^{-6}}=19.4 \mathrm{~Pa}$
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