Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
1 gm of water at 100oC is completely converted into steam at 100oC . 1 gm steam occupies a volume of 1650 cc. (Neglect the volume of 1 gm of water at 100oC). At the pressure of 105 Nm2, latent heat of steam is 540 calgm 1 calorie=4.2 Joule. The increase in the internal energy in Joules is 
PhysicsThermodynamicsNEET
Options:
  • A 2310
  • B 2103
  • C 1650
  • D 2150
Solution:
2225 Upvotes Verified Answer
The correct answer is: 2103
Q=540 cal

W=Po V2-V1

V 1 =0

   W=105 165×10-6=165 J

   U=540×4.2-165=2103 J

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.