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Question: Answered & Verified by Expert
\( 1 \) litre of a hydrocarbon weighs as much as one litre of \( \mathrm{CO}_{2} \) at same \( \mathrm{P} \) and \( \mathrm{T} \). Then the molecular formula of the
hydrocarbon is:
ChemistrySome Basic Concepts of ChemistryJEE Main
Options:
  • A \( \mathrm{C}_{3} \mathrm{H}_{8} \)
  • B \( \mathrm{C}_{2} \mathrm{H}_{6} \)
  • C \( \mathrm{C}_{2} \mathrm{H}_{4} \)
  • D \( \mathrm{C}_{3} \mathrm{H}_{6} \)
Solution:
2534 Upvotes Verified Answer
The correct answer is: \( \mathrm{C}_{3} \mathrm{H}_{8} \)

1 litre of a hydrocarbon weighs as much as one litre of CO2.

Hence, 22.4 L of hydrocarbon will weigh as much as 22.4 L of CO2.

22.4 L of CO2 weighs 12+162=44 g at NTP.

Out of all hydrocarbons, C3H8 only weighs 123+18=44 g.

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