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Question: Answered & Verified by Expert
\( 1 \mathrm{~L} \) of \( 2 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH} \) is mixed with \( 1 \mathrm{~L} \) of \( 3 \mathrm{M} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \) to form an ester. The rate of the
reaction with respect to the initial rate when each solution is diluted with an equal volume of
water will be
ChemistryChemical KineticsKCETKCET 2019
Options:
  • A \( 0.5 \) times
  • B \( 4 \) times
  • C \( 0.25 \) times
  • D \( 2 \) times
Solution:
1390 Upvotes Verified Answer
The correct answer is: \( 0.25 \) times
(C)
Esterification is a second order reaction
$\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \rightarrow \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H} 5+\mathrm{H}_{2} \mathrm{O}$
$\mathrm{r}=\mathrm{k}\left[\mathrm{CH}_{3} \mathrm{COOH}\right]\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right]$
Order $=2$
When equal volume of two solutions are mixed, concentration of the solutions reduces to half the initial value. Hence,
rate of reaction gets reduced to $\frac{1}{4}$ initial rate.

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