Search any question & find its solution
Question:
Answered & Verified by Expert
1 mole of gas $A$ and 1 mole of gas $B$ at $27^{\circ} \mathrm{C}$ were pumped into a $24.6 \mathrm{~L}$ volume pre- evacuated isolated flask. The catalyst coated inside the flask catalyses the following reaction
$A(g)+B(g) \longrightarrow 2 D(g)$. The kinetic energy of $D$ is $98.03 \mathrm{~L} \mathrm{~atm}$. Calculate the pressure realised at the end of the reaction.
Options:
$A(g)+B(g) \longrightarrow 2 D(g)$. The kinetic energy of $D$ is $98.03 \mathrm{~L} \mathrm{~atm}$. Calculate the pressure realised at the end of the reaction.
Solution:
1531 Upvotes
Verified Answer
The correct answer is:
$2.66 \mathrm{~atm}$
Kinetic energy for $n$ moles is given by
$$
\text { K.E. }=\frac{3}{2} p V
$$
where, $p$ is the pressure exerted by the gas and $V$ is the volume occupied by gas.
$$
A(g)+B(g) \longrightarrow 2 D(g)
$$
Given: Kinetic energy of $D=98.03 \mathrm{~L} \mathrm{~atm}$
$$
\begin{aligned}
& \therefore \text { K.E. } \quad=\frac{3}{2} p V \\
& 98.03 \mathrm{~L} \mathrm{~atm}=\frac{3}{2} \times p \times 24.6 \mathrm{~L} \\
& p=266 \mathrm{~atm}
\end{aligned}
$$
$$
\text { K.E. }=\frac{3}{2} p V
$$
where, $p$ is the pressure exerted by the gas and $V$ is the volume occupied by gas.
$$
A(g)+B(g) \longrightarrow 2 D(g)
$$
Given: Kinetic energy of $D=98.03 \mathrm{~L} \mathrm{~atm}$
$$
\begin{aligned}
& \therefore \text { K.E. } \quad=\frac{3}{2} p V \\
& 98.03 \mathrm{~L} \mathrm{~atm}=\frac{3}{2} \times p \times 24.6 \mathrm{~L} \\
& p=266 \mathrm{~atm}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.