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$$
\frac{\cos x}{1+\sin x}+\tan x=
$$
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\frac{\cos x}{1+\sin x}+\tan x=
$$
Solution:
2727 Upvotes
Verified Answer
The correct answer is:
$\sec x$
$\begin{aligned} & \frac{\cos x}{1+\sin x}+\tan x \\ & =\frac{\cos x(1-\sin x)}{(1+\sin x)(1-\sin x)}+\tan x \\ & =\frac{\cos x \times(1-\sin x)}{1-\sin ^2 x}+\tan x=\frac{1-\sin x}{\cos x}+\tan x \\ & =\sec x-\tan x+\tan x=\sec x\end{aligned}$
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