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Question: Answered & Verified by Expert
1+tanxtanx+atanxtanx+adx=
MathematicsIndefinite IntegrationAP EAMCETAP EAMCET 2022 (04 Jul Shift 2)
Options:
  • A tanalogsecx+a+logsecx+C
  • B cotalogsinx-logsinx+a+C
  • C tanalogcosxsinx+a+C
  • D cotalogsinx+acosx+a+C
Solution:
2041 Upvotes Verified Answer
The correct answer is: cotalogsinx-logsinx+a+C

I=1+tanxtanx+atanxtanx+adx

We know tana=tanx+a-x=tanx+a-tanx1+tanxtanx+a

So, I=cotatanx+a-tanxtanx+atanxdx

=cota1tanx-1tanx+adx

=cotalogsinx-logsinx+a+C

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