∫ 1 + x + x + x 2 x + 1 + x d x =

Question

∫ 1 + x + x + x 2 x + 1 + x d x =, 1 2 1 + x + c, 2 3 ( 1 + x ) 3 2 + c, 1 + x + c, 2 ( 1 + x ) 3 2 + c

MARKS App · Accepted Answer

∫ 1 + x + x + x 2 x + 1 + x d x = ∫ ( 1 + x ) 2 + x 1 + x x + 1 + x d x = ∫ 1 + x [ 1 + x + x ] x + 1 + x d x = ∫ ( 1 + x ) 1 2 d x Using ∫ x n d x = x n + 1 n + 1 + c , = ( 1 + x ) 3 2 3 2 + c = 2 3 1 + x 3 2 + c .

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