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Question: Answered & Verified by Expert
1022 gas molecules each of mass 10-26 kg collide with a surface (perpendicular to it) elastically per second over an area 1 m2 with a speed of 104 m s-1. The pressure exerted by the gas molecules will be
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Options:
  • A 2 m-2
  • B 4 m-2
  • C 8 m-2
  • D 16 m-2
Solution:
1813 Upvotes Verified Answer
The correct answer is: 2 m-2
v=104 m s-1
m=10-26
n=1022
A=1 m2

Δp=2mnv

Δp=2×1022×10-26×104=2

P=FA=2 N m-2

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