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$10 \mathrm{~cm}^{3}$ of $0.1 \mathrm{~N}$ monobasic acid requires $15 \mathrm{~cm}^{3}$ of sodium hydroxide solution whose normality is
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$0.066 \mathrm{~N}$
$\begin{aligned} V_{1} &=10 \mathrm{~cm}^{3} \\ V_{2} &=15 \mathrm{~cm}^{3} \\ N_{1} &=0.1 \mathrm{~N} \\ N_{2} &=? \\ N_{1} V_{1} &=N_{2} V_{2} \\ N_{2} &=\frac{0.1 \times 10}{15}=0.066 \mathrm{~N} \end{aligned}$
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