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Question: Answered & Verified by Expert
10 g of MgCO3 decomposes on heating to 0.1 mole CO2 and g MgO. The percent purity of MgCO3 is
(Given that atomic weights of  Mg,C and O are 24, 12 and 16 u)
ChemistrySome Basic Concepts of ChemistryJEE Main
Options:
  • A 44%
  • B 54%
  • C 74%
  • D 84%
Solution:
2100 Upvotes Verified Answer
The correct answer is: 84%
MgC O 3 decomposes as below:

MgC O 3 MgO+C O 2

mole ratio =1:1:1

Thus 0.1 mole of C O 2 will be produced by 0.1 mole of MgC O 3 .

Mass of MgC O 3 in 10g sample =0.1×84=8.4 g

Percent purity = 8.4 10 ×100=84%

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