$10 \mathrm{~g}$ of $\mathrm{NaOH}$ is dissolved in $500 \mathrm{~mL}$ of aqueous solution. Calculate the molarity of this solution? (Given, formula weight of $\mathrm{NaOH}=40$ )

Question

$10 \mathrm{~g}$ of $\mathrm{NaOH}$ is dissolved in $500 \mathrm{~mL}$ of aqueous solution. Calculate the molarity of this solution? (Given, formula weight of $\mathrm{NaOH}=40$ ), $0.5 \times 10^{-3} \mathrm{M}$, $0.4 \mathrm{M}$, $0.25 \times 10^{-3} \mathrm{M}$, $0.5 \mathrm{M}$

MARKS App · Accepted Answer

$\therefore$ Molarity $=\frac{\text { Mass of solute }\left(\text { in } \mathrm{gL}^{-1}\right)}{\text { Molar of solute }\left(\text { in } \mathrm{g} \mathrm{mol}^{-1}\right)}$ $=\frac{\frac{10}{500} \times 1000}{40} \mathrm{M}=0.5 \mathrm{M}$

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