Search any question & find its solution
Question:
Answered & Verified by Expert
10 men and 6 women are to be seated in a row so that no two women sit together. The number of ways they can be seated, is
Options:
Solution:
2675 Upvotes
Verified Answer
The correct answer is:
$\frac{11 ! 10 !}{5 !}$
W W W W W W W W W First, we arrange 10 men in a row at alternate position.
So, number of ways formula $=10$ !
Now, 6 women can arrange in 11 positions
So, number of ways for women $={ }^{11} P_6$
Required number of
$$
\begin{aligned}
S & =10 ! \times{ }^{11} P_6 \\
& =\frac{10 ! 11 !}{5 !}
\end{aligned}
$$
So, number of ways formula $=10$ !
Now, 6 women can arrange in 11 positions
So, number of ways for women $={ }^{11} P_6$
Required number of
$$
\begin{aligned}
S & =10 ! \times{ }^{11} P_6 \\
& =\frac{10 ! 11 !}{5 !}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.