10 mL of 1 mM surfactant solution forms a monolayer covering 0 . 24 c m 2 on a polar substrate. If the polar head is approximated as cube, what is its edge length?

Question

10 mL of 1 mM surfactant solution forms a monolayer covering 0 . 24 c m 2 on a polar substrate. If the polar head is approximated as cube, what is its edge length?, 2.0 pm, 2.0 nm, 1.0 pm, 0.1 nm

MARKS App · Accepted Answer

Millimoles = 10 × 1 0 - 3 = 1 0 - 2 Moles = 1 0 - 5 No. of molecules = 6 × 1 0 23 × 1 0 - 5 = 6 × 1 0 18 Surface area ocupied by one molecule = 0.24 6 × 1 0 18 = 0.04 × 1 0 - 18 c m 2 4 × 1 0 - 20 = x 2 [ ∵ x = edge length ] x = 2 × 1 0 - 10 cm = 2 pm

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