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$10 \mathrm{~mL}$ of liquid carbon disulphide (specific gravity 2.63) is burnt in oxygen. Find the volume of the resulting gases measured at STP.
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The correct answer is:
$23.25 \mathrm{~L}$
$1 \mathrm{~mL}$ of $\mathrm{CS}_2$ weighs $2.63 \mathrm{~g}$
$10 \mathrm{~mL}$ of $\mathrm{CS}_2$ weighs $26.3 \mathrm{~g}$
$\because \quad 76 \mathrm{~g}$ of $\mathrm{CS}_2$ will yield $67.2 \mathrm{~L}$ of a mixture of $\mathrm{CO}_2$ and $\mathrm{SO}_2$ at STP
$\therefore \quad 26.3$ gof $\mathrm{CS}_2$ would yield $\frac{67.2}{76} \times 26.3=23.25 \mathrm{~L}$
$10 \mathrm{~mL}$ of $\mathrm{CS}_2$ weighs $26.3 \mathrm{~g}$
$\because \quad 76 \mathrm{~g}$ of $\mathrm{CS}_2$ will yield $67.2 \mathrm{~L}$ of a mixture of $\mathrm{CO}_2$ and $\mathrm{SO}_2$ at STP
$\therefore \quad 26.3$ gof $\mathrm{CS}_2$ would yield $\frac{67.2}{76} \times 26.3=23.25 \mathrm{~L}$
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