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Question: Answered & Verified by Expert
10 resistors, each of resistance R are connected in series to a battery of emf E and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased n times. The value of n is:
PhysicsCurrent ElectricityNEETNEET 2023 (All India)
Options:
  • A 1000
  • B 10
  • C 100
  • D 1
Solution:
2092 Upvotes Verified Answer
The correct answer is: 100

When the resistors are connected in series with the battery, the equivalent resistance Rs can be written as

Rs=R+R+....10 times=10R   ...1

Hence, the current is is given by

is=ERs=E10R   ...2

When the resistors are connected in parallel, the equivalent resistance Rp is given by

Rp=11R+1R+.... 10 times= R10   ...3

Hence, the current ip is given by

ip=ERp=ER10=10ER   ...4

Divide equation (4) by equation (2) to obtain the required value of the multiplier n.

ipis=10ERE10R= 100

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