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$100 \mathrm{~cm}^3$ of a given sample of $\mathrm{H}_2 \mathrm{O}_2$ gives $1000 \mathrm{~cm}^3$ of $\mathrm{O}_2$ at S.T.P. The given sample is
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The correct answer is:
10 volume $\mathrm{H}_2 \mathrm{O}_2$
$$
\begin{gathered}
2 \mathrm{H}_2 \mathrm{O}_2 \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2 \\
100 \mathrm{~mL} \\
1000 \mathrm{~mL}
\end{gathered}
$$
or $1 \mathrm{~mL}$ of $\mathrm{H}_2 \mathrm{O}_2$ will give $10 \mathrm{~mL}$ of $\mathrm{O}_2$ at $\mathrm{STP}$
Thus its volume strength is 10 volume.
\begin{gathered}
2 \mathrm{H}_2 \mathrm{O}_2 \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2 \\
100 \mathrm{~mL} \\
1000 \mathrm{~mL}
\end{gathered}
$$
or $1 \mathrm{~mL}$ of $\mathrm{H}_2 \mathrm{O}_2$ will give $10 \mathrm{~mL}$ of $\mathrm{O}_2$ at $\mathrm{STP}$
Thus its volume strength is 10 volume.
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