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$100 \mathrm{~mL}$ of $0.2 \mathrm{M}$ acetic acid is completely neutralised using a standard solution of $\mathrm{NaOH}$. The volume of ethane obtained at STP after complete electrolysis of the resulting solution is
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The correct answer is:
$0.224 \mathrm{~L}$
Given moles of acetic acid
$$
\begin{array}{r}
=\frac{0.2 \times 100}{1000}=0.02 \text { moles } \\
2 \mathrm{CH}_3 \mathrm{COOH} \longrightarrow \mathrm{C}_2 \mathrm{H}_6+2 \mathrm{CO}_2+\mathrm{H}_2
\end{array}
$$
2 moles of $\mathrm{CH}_3 \mathrm{COOH}$ gives 1 mole of ethane $=22.4 \mathrm{~L}$
0.02 moles of $\mathrm{CH}_3 \mathrm{COOH}$ will give ethane
$$
=\frac{22.4 \times 0.02}{2}=0.224 \mathrm{~L}
$$
$\therefore 0.224 \mathrm{~L}$ of ethane is obtained.
$$
\begin{array}{r}
=\frac{0.2 \times 100}{1000}=0.02 \text { moles } \\
2 \mathrm{CH}_3 \mathrm{COOH} \longrightarrow \mathrm{C}_2 \mathrm{H}_6+2 \mathrm{CO}_2+\mathrm{H}_2
\end{array}
$$
2 moles of $\mathrm{CH}_3 \mathrm{COOH}$ gives 1 mole of ethane $=22.4 \mathrm{~L}$
0.02 moles of $\mathrm{CH}_3 \mathrm{COOH}$ will give ethane
$$
=\frac{22.4 \times 0.02}{2}=0.224 \mathrm{~L}
$$
$\therefore 0.224 \mathrm{~L}$ of ethane is obtained.
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