100 mL of Na 3 PO 4 solution contains 3 . 45 g of sodium. The molarity of the solution is ..... × 10 - 2 mol L - 1 . (Nearest integer) [Atomic Masses - Na : 23 . 0 u , O : 16 . 0 u , P : 31 . 0 u ]

Question

100 mL of Na 3 PO 4 solution contains 3 . 45 g of sodium. The molarity of the solution is ..... × 10 - 2 mol L - 1 . (Nearest integer) [Atomic Masses - Na : 23 . 0 u , O : 16 . 0 u , P : 31 . 0 u ],

MARKS App · Accepted Answer

Number of mole of Na + ion = 3 . 45 23 mol So number of mole of Na 3 PO 4 = 3 . 45 3 × 23 = 0 . 050 mol Molarity = 0 . 050 100 × 1000 = 0 . 50 = 50 × 10 - 2 M

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