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$1.2 \mathrm{~g}$ of organic compound of Kjeldahlization liberates ammonia which consumes $30 \mathrm{~cm}^{3}$ of $1 \mathrm{~N} \mathrm{HCl}$. The percentage of nitrogen in the organic compound is
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The correct answer is:
35
Percentage of nitrogen
$$
\begin{aligned}
&=\frac{1.4 \times \mathrm{N} \text { of acid } \times \mathrm{Vol} \text {. used with } \mathrm{NH}_{3}}{\text { Weight of organic compound }} \\
&=\frac{1.4 \times 1 \times 30}{1.2} \\
&=35
\end{aligned}
$$
$$
\begin{aligned}
&=\frac{1.4 \times \mathrm{N} \text { of acid } \times \mathrm{Vol} \text {. used with } \mathrm{NH}_{3}}{\text { Weight of organic compound }} \\
&=\frac{1.4 \times 1 \times 30}{1.2} \\
&=35
\end{aligned}
$$
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