1.245 g sample of C u S O 4 . x H 2 O dissolved in water and excess of H 2 S was passed. The filtrate contains liberated H 2 S O 4 which requires 20 ml N/2NaOH solutions for neutralization. Calculate the value of x?

Question

1.245 g sample of C u S O 4 . x H 2 O dissolved in water and excess of H 2 S was passed. The filtrate contains liberated H 2 S O 4 which requires 20 ml N/2NaOH solutions for neutralization. Calculate the value of x?, 3, 2, 4, 5

MARKS App · Accepted Answer

M eq . of CuSO 4 × xH 2 O = M eq . H 2 SO 4 = M eq . NaOH M eq . CuSO 4 = M eq . NaOH 10 3 × wt . Mol . mass × v .f . = N × V 1.245 M × 2 × 10 3 = 4 20 × 2 M = 1.245 × 2 × 10 3 × 10 M = 249 Molecular weight of C u S O 4 . x H 2 O = 63.5 + 32 + 64 + 18 x = 159.5 + 18 x 249 = 159 .5 + 18x So, x = 5 .

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