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$138 \mathrm{~g}$ of ethyl alcohol is mixed with $72 \mathrm{~g}$ of water. The ratio of mole fraction of alcohol to water is
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$3: 4$
$\begin{aligned} & \text { Number of moles of ethyl alcohol }=\frac{138}{46}=3 \\ & \text { Number of moles of water }=\frac{72}{18}=4 \\ & X_{\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}}=\frac{3}{3+4}=\frac{3}{7} \\ & X_{\mathrm{H}_2 \mathrm{O}}=\frac{4}{3+4}=\frac{4}{7} \\ & \frac{X_{\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}}}{X_{\mathrm{H}_2 \mathrm{O}}}=\frac{3 / 7}{4 / 7}=\frac{3}{4}\end{aligned}$
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