Search any question & find its solution
Question:
Answered & Verified by Expert
$1.5 \mathrm{~g}$ of $\mathrm{CdCl}_2$ was found to contain $0.9 \mathrm{~g}$ of $\mathrm{Cd}$. Calculate the atomic weight of Cd.
Options:
Solution:
2536 Upvotes
Verified Answer
The correct answer is:
106.5
$\begin{aligned}
\% \text { of } \mathrm{Cd} \text { in } \mathrm{CdCl}_2= & \frac{0.9}{1.5} \times 100 \\
& =60 \%
\end{aligned}$
Therefore, $\%$ of $\mathrm{Cl}_2$ in $\mathrm{CdCl}_2=100-60=40 \%$
$\begin{aligned} & \because 40 \% \text { part }\left(\mathrm{Cl}_2\right) \text { has atomic weight } \\ & =2 \times 35.5=71.0 \\ & \therefore 60 \% \text { part (Cd) has atomic weight } \\ & =\frac{71.0 \times 60}{40} \\ & =106.5 \\ & \end{aligned}$
\% \text { of } \mathrm{Cd} \text { in } \mathrm{CdCl}_2= & \frac{0.9}{1.5} \times 100 \\
& =60 \%
\end{aligned}$
Therefore, $\%$ of $\mathrm{Cl}_2$ in $\mathrm{CdCl}_2=100-60=40 \%$
$\begin{aligned} & \because 40 \% \text { part }\left(\mathrm{Cl}_2\right) \text { has atomic weight } \\ & =2 \times 35.5=71.0 \\ & \therefore 60 \% \text { part (Cd) has atomic weight } \\ & =\frac{71.0 \times 60}{40} \\ & =106.5 \\ & \end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.