16 g of a radio active substance is reduced to 0 .5 g after 1 hour. The half life of the radioactive substance in minutes is

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Question: Answered & Verified by Expert

16 g

of a radio active substance is reduced to

0 .5 g

after

1

hour. The half life of the radioactive substance in minutes is

ChemistryChemical KineticsJEE Main

Solution:

2563 Upvotes Verified Answer

The correct answer is: 12

λ = \frac{1}{t} l n \frac{16}{0.5}

λ = 5 \times l n 2

t_{\frac{1}{2}} = \frac{l n 2}{λ} = \frac{1}{5} h r = 12 m i n

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