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$16 \mathrm{~g}$ of oxygen and $3 \mathrm{~g}$ of hydrogen are mixed and kept at $760 \mathrm{~mm}$ pressure and $0^{\circ} \mathrm{C}$. The total volume occupied by the mixture will be nearly
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$44800 \mathrm{~ml}$
$n$ of $O_2=\frac{16}{32}=\frac{1}{2}$
n of $\mathrm{H}_2=\frac{3}{2}$
Total no. of moles $=\frac{3}{2}+\frac{1}{2}=2$
$V=\frac{n R T}{P}=\frac{2 \times .082 \times 273}{1}=44.8 \mathrm{lit}=44800 \mathrm{ml}$
n of $\mathrm{H}_2=\frac{3}{2}$
Total no. of moles $=\frac{3}{2}+\frac{1}{2}=2$
$V=\frac{n R T}{P}=\frac{2 \times .082 \times 273}{1}=44.8 \mathrm{lit}=44800 \mathrm{ml}$
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