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Question: Answered & Verified by Expert
π184π92sinxsinx+cosxdx=
MathematicsIndefinite IntegrationMHT CETMHT CET 2019 (Shift 1)
Options:
  • A 7π36
  • B 5π36
  • C 7π18
  • D 5π18
Solution:
2127 Upvotes Verified Answer
The correct answer is: 7π18
Let =lπ184π92sinxsinx+cosxdx
=2π184π9sinxsinx+cosxdx …(i)
=2π184π9sin4π9+π18-xsin4π9+π8-x+cos4π9+π8-xdx
abfxdx=abfa+b-xdx
l=2π184π9cosxcosx+sinxdx …(ii)
On adding Eqs. (i) and (ii), we get
2l=2π184π9dx=2xπ184π9
=24π9-π18=27π18
l=7π18

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